Question

Find a relationship between x and y such that

The point P(x, y) is equidistant from (3,6) and

(-3,4)​

Answer 1

Answer:

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Answer 2

Answer:

3x+y=5

Step-by-step explanation:

p

(-3, 4) ___________(x, y) ___________(3,6)

using distance formula.

√(x+3)^2+(y-4)^2=√(3-x)^2+(6-y)^2

x^2+9+6x+y^2+16-8y=9+x^2-6x+36+y^2-12y

6x+16-8y=-6x+36-12y

6x+6x-8y+12y=36-16

12x+4y=20

3x+y=5