Question

find a relationship between X and Y such that the point (X, Y) is equal distance from the point (7,1) and (3,5)​

Answer 1

Step-by-step explanation:

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP2=BP2

(x−7)2+(y−1)2=(x−3)2+(y−5)2

x2−14x+49+y2−2y+1=x2−6x+9+y2−10y+25

x−y=2

Answer 2

Answer:

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP²=BP²

(x−7) ² +(y−1)²=(x−3)²+(y−5)²

x²−14x+49+y² −2y+1=x²−6x+9+y²−10y+25

x−y=2