Find a remainder when dividing 1! + 2! + 3! + ... + 15! by 30.
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8
Answer:
answer of the given quetion is 3
Answered by
2
Solution :-
→ 1! = 1
→ 2! = 1 * 2 = 2
→ 3! = 1 * 2 * 3 = 6
→ 4! = 1 * 2 * 3 * 4 = 24
→ 5! = 1 * 2 * 3 * 4 * 5 = 120 = Divisible by 30 .
Now, all factorials after 5 will also be multiple of 120 . So they will be divisible by 30 .
then,
→ (1! + 2! + 3! + ... + 15!) ÷ 30
→ (1 + 2 + 6 + 24) ÷ 30
→ 33 ÷ 30
→ 3 Remainder .
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