Math, asked by pratikshakadam0906, 22 days ago

Find a remainder when dividing 1! + 2! + 3! + ... + 15! by 30.​

Answers

Answered by polinaraviteja9
8

Answer:

answer of the given quetion is 3

Answered by RvChaudharY50
2

Solution :-

→ 1! = 1

→ 2! = 1 * 2 = 2

→ 3! = 1 * 2 * 3 = 6

→ 4! = 1 * 2 * 3 * 4 = 24

→ 5! = 1 * 2 * 3 * 4 * 5 = 120 = Divisible by 30 .

Now, all factorials after 5 will also be multiple of 120 . So they will be divisible by 30 .

then,

→ (1! + 2! + 3! + ... + 15!) ÷ 30

→ (1 + 2 + 6 + 24) ÷ 30

→ 33 ÷ 30

3 Remainder .

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