Question

find a rod of the greatest length which can measure exactly 42m,49,and 63m. Find also the numbers of rod of equal length contain in each length
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Answer 1

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42 = 2×3×7

49 = 7×7

84 = 2×2×3×7

HCF of 42, 49 and 84 is 7

the greatest length of the rod which can measure exactly 42m,49m and 84m is 7 m

the number of times the rod of 7m is contained in 42m = 6 times

the number of times the rod of 7m is contained in 49m = 7 times

the number of times the rod of 7m is contained in 84m = 12 times

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