find a root of an equation f(x)=2x^2-2x-5 using bisection method.
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i)
If 2x
2
+kx+3=0 has equal roots, then b
2
−4ac=0.
Here, a=2,b=k,c=3
x
2
+kx+3=0
b
2
−4ac=0
k
2
−4(2)(3)=0
k
2
=24
k=±
24
=±2
6
ii)
If kx
2
−2kx+6=0 has equal roots, then b
2
−4ac=0.
Here, a=k,b=−2k,c=6
kx(x−2)+6=0
kx
2
−2kx+6=0
4k
2
−4(k)(6)=0
4k
2
−24k=0
4k(k−6)=0
For k=0, equation is not quadratic.
k=6
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