Question

find a root of equation x²+5x+6=0using NR method​

Answer 1

$\huge\underline{\underline{\mathtt{\blue{Answer}}}}$

${x}^{2} + 5x + 6 \\ {x}^{2} - x + 6x + 6 \\ x(x - 1) + 6(x - 1) \\ (x - 1)(x + 6)$

$equating \: \: each \: \: to \: \: 0 \\ x- 1 = 0 \\ {\boxed{x = 1}} \\ and \: \\ x + 6 = 0 \\{\boxed{ x = - 6}}$

Hence, value of x is 1 and -6.

Answer 2

Answer:

$\huge\underline\mathfrak\purple{Answer}$

Value of c is 1 and-6