Question

find a root of equation x²+5x+6=0using NR method​

Answer 1

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${x}^{2} + 5x + 6 \\ {x}^{2} - x + 6x + 6 \\ x(x - 1) + 6(x - 1) \\ (x - 1)(x + 6)$

$equating \: \: each \: \: to \: \: 0 \\ x- 1 = 0 \\ {\boxed{x = 1}} \\ and \: \\ x + 6 = 0 \\{\boxed{ x = - 6}}$

Hence, value of x is 1 and -6.

Answer 2

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The value of x is 1 and -6 .

Refer the attachment

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