Find a side and perimeter of a square whose diagonal is 13 root 2 cm.
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Answered by
5
Answer:
by using Pythagoras thorem
let AD be diagonal=13√2
all sides of square are equal
So-----
AD^2=AB2 +BD2
(13√2) square =2AB ( Ab = bd sides of square)
338= 2AB
338 / 2 =AB
169=AB
AB =13
SIDE OF THE SQUARE IS 13 CENTIMETER
PERIMETER OF SQUARE = 4 X SIDE
= 13 multiply 4
=92
Step-by-step explanation:
So the perimitre is 92 ans side of square is 13
hope it helped
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Answer:
Here is your answer I hope it is helpfull.
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