Question

find
a.sin^2 60°+sin^2 45°
b.3coe^2 30°+tan^2 60°​

Answer 1

Answer:

a.) 5/4 b) 21/4

Step-by-step explanation:

sin^2 60+sin^2 45

(√3/2)^2+(1/2)^2

3/4+1/2

3+2/4=5/4

b) 3(√3/2)^2+(√3)^2

3*3/4+3

9/4+3/1=9+12/4

=21/4

Answer 2

Answer:

a.answer = 1

b.answer= 12

Step-by-step explanation:

$\sin {}^{2} ( 60 ) = | \frac{ \sqrt{3} }{2} | {}^{2} = \frac{3}{4}$

$\sin {}^{2} (45) = | \frac{1}{ \sqrt{2} } | {}^{2} = \frac{1}{4}$

$therefore \\ \sin {}^{2} (60) + \sin {}^{2} (45) = \frac{3}{4} + \frac{1}{4} = \frac{4}{4} = 1$

é

$3 \cot {}^{2} (30) + \tan {}^{2} (60) = 3 \times | \sqrt{3} | {}^{2} + | \sqrt{3} | {}^{2} = 3 \times 3 + 3 = 9 + 3 = 12$

follow and mark as brainliest if helpful