Question

Find a smallest number which when subtracted from 1024 the difference is a perfect cube

Answer 1

Answer:

63

Step-by-step explanation:

${31}^{2} = 961 \\ {32}^{2} = 1024 \\ 1024 - 961 = 63 \\ answer \: is \: 63 \: beacuse \: 1024 - 63 = 961 = {31}^{2}$

Answer 2

Answer:

24

Step-by-step explanation:

cause assume the equation

1024-x=y^3

here x, y are integers

also x needed to be minimum

thus x= minimum

manipulating the equation 1024 - y^3=x

thus 1024-y^3=min, if y=10 this will be min , (if y=11 it's not possibly good as negative results)

thus x=1024-1000=24