Question

find a smallest square number which is divisible by each of the number 10,15 and 20 ...

Answer 1

Answer:

L.C.M. of 8, 15 and 20 is 120.

Prime factors of 120 = 2 x 2 x 2 x 3 x 5

Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

\therefore120\times2\times3\times5=3600

Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600

Answer 2

Answer:

bro I think it's 5 if it's not am so sorry I know about ur exam