Find 'a" so that (3,a) lies on the line represented by 2x-3y-5=0. Also , find the coordinates of the point where line cuts the x-axis.
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Answered by
659
Hi ,
i ) It is given that ,
( 3 , a ) lies on the line 2x - 3y - 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3a - 5 = 0
6 - 3a - 5 = 0
1 - 3a = 0
1 = 3a
1/3 = a
a = 1/3
ii ) If the line cuts the x - axis ,
to find the coordinates , put y = 0
in the equation , we get
2x - 3 × 0 - 5 = 0
2x - 5 = 0
2x = 5
x = 5/2
Therefore ,
Required point = ( 5/2 , 0 )
I hope this helps you.
: )
i ) It is given that ,
( 3 , a ) lies on the line 2x - 3y - 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3a - 5 = 0
6 - 3a - 5 = 0
1 - 3a = 0
1 = 3a
1/3 = a
a = 1/3
ii ) If the line cuts the x - axis ,
to find the coordinates , put y = 0
in the equation , we get
2x - 3 × 0 - 5 = 0
2x - 5 = 0
2x = 5
x = 5/2
Therefore ,
Required point = ( 5/2 , 0 )
I hope this helps you.
: )
Answered by
218
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