Find a So that 3a + 2, 3a - 1, 5a + 4 are in AP.
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Answer:
a = - 4
Step-by-step explanation:
a1 = 3a + 2
a2 = 3a - 1
a3 = 5a + 4
d1(common difference)1 = a2 - a1
= (3a - 1) - (3a + 2)
d2(common difference)2 = a3 - a2
= (5a + 4) - (3a - 1)
= (3a - 1) - (3a + 2) = (5a + 4) - (3a - 1)
= 3a - 1 - 3a - 2 = 5a + 4 - 3a + 1
= -3 = 2a + 5
= -3 - 5 = 2a
-8 = 2a
a = - 8/2
a = - 4
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