Question

Find a square number which is divisible by each 6.9,15

Answer 1

Since, we wanted smallest perfect square number divisible by 6, 9 and 15. So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 * 5 to LCM (90).

= 90 x 2 x 5

= 90 x 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

SOLUTION IN THE ABOVE PIC. IS ALSO

FOR REFERENCE

Hope it helped