find a t12 in the AP 4,1,- 2...
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Answered by
1
tn=a+(n-1)d
t12=4+(12-1)(-3)
=-29
t12=4+(12-1)(-3)
=-29
Answered by
0
hii,
the value t12 will be -29....
the value t12 will be -29....
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