Math, asked by Manish9106323, 1 year ago

Find A tan² A = 3(sec A - 1)

Answers

Answered by kavithadurai20oyfx68
0
tan² A = 3(sec A - 1)
Sec²A-1 = 3(sec A - 1)
(sec A - 1)(sec A + 1)=3(sec A - 1)
[(sec A - 1)(sec A + 1)] /(sec A - 1) = 3

sec A + 1 =3
SecA = 3-1

SecA = 2
A = 45
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