Question

find (a) The path of projectile (b) time of flight (c) maximun height when projectile is projected with velocity V making an angle of theta with vertical direction.(5 marks)​

Answer 1

Answer:

Explanation:a) the path of a projectile is its trajectory which is a parabola.

b) The time taken by the projectile to reach the horizontal plane of projection after being projected is called time of flight. This is given by the formula

t = 2u sinΦ/g

c) The maximum height attained by a projectile is given by

H (max) = u^2 sin^2Φ/2g

Note: I am taking theta as Φ