Question

Find (a) the projection of à = 2i- 3j+6k onto the vector B = i + 2j + 2k. (b) determine the angle between the vectors à and B​

Answer 1

Answer:

Explanation:

cosФ=A.B/AB

A=√(2²+3²+6²)=√49=7

B=√(1²+2²+2²)=√9=3

cosФ=(2i- 3j+6k).(i + 2j + 2k)/(7x9)

cosФ=(2- 6+12)/(7x9)

cosФ=8/63

Ф=cos-1(8/63)