Find (a), the total number and (b) the rotal mass of protons in 34 mg of NH3 at STP.
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Answer:(In Explanation)
Explanation:
(a)Number of protons present in 1 molecule of ammonia =7+3=10.
Number of molecules present in 34 mg of ammonia is
17
6.023×10
23
×34×10
−3
=1.2044×10
21
.
Total number of protons present in 34mg of ammonia=10×1.2044×10
21
=1.2044×10
22
.
(b) Total mass of protons present in 34 mg of ammonia at STP is:
1.6726×10
−27
×1.204×10
22
=2.0138×10
−5
kg.
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