Chemistry, asked by isowk, 11 months ago

Find (a) the total number and (b) the total mass of neutrons in 7 mg of 14C. (Assume that mass of a neutron = 1.675 × 10^–27 kg).​

Answers

Answered by RoYxY
8

Answer:

here \: is \: your \: answer....

Mass of one neutron

= 1.675 × 10^–27 kg

1 mole of Carbon atom

= 6.023×10²³ atoms

Number of neutrons in 1 carbon atom

= 14-6= 8

So total number of neutrons in 14g of Carbon

= 6.023×10²³×8 neutrons

So 7mg of Carbon will contain

= 6.023 x 10²³ x 8 x 7 x 10^-3 / 14

= [3.37288×10²²]/14

= 2.4092×10²¹ neutrons

So, Mass of 2.4092×1021 neutrons

= [2.4092×10²¹] × [1.675 × 10^–24]

= 4.035×10^–3 g

So, in 7 mg of carbon total number of neutrons is 2.41×10²¹ and the total mass of the neutrons is 4.035× 10^–3 g

Answered by Anonymous
17

 \:\:  \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}

number of electrons in 14c=6

therefore number of protons=14-6=8

now....

we know ....1g=1000mg

now mass of 14C= 14g=14×1000mg

will have =(8×6.023×10²³ )numbers of neutrons

therefore ....

in 7mg... number of neutrons is ....

=

 \frac{8 \times 6.023 \times 10 {}^{23} }{14000}  \times 7 \\  = 2.4092 \times 10 {}^{21}

mass of a single neutron is =1.675×10^-27kg

therefore mass of 2.4092×10^21 number of neutrons is

 = 1.675  \times 10 {}^{ - 27}  \times 2.4092 \times 10 {}^{21} \\  =  4.035 \times 10 {}^{ - 6} kg

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