Find a two digit no. If it is 36 less than the no. Obtained by reversing it's digit. The sum of the digit is 12 ??
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Let us consider the unit digit be ‘x’
and tens digit be ‘y’
So, the number is =x+10y
By reversing the digits
Unit digit be ‘y’
and tens digit be ‘x’
The number is y+10x=36
Now by equating both numbers,
x+10y–y–10x=36
−9x+9y=36
(y–x)=36/9
y–x=4
∴ The difference between digits of the 2−digit number is y–x=4.
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