find a two digit number divisible by 2 full feeling the following condition in
(a) whose digit add up to 5
(b) whose tens digit is three times the ones digit
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Let the digit in the units place be x and the digit in the ten's place by y. Then number =10y+x
According to the given condition, we have y=3x -----(1)
Number obtained by reversing the digits =10x+y
If the number is decreased by 54, the digits are reversed
∴ number −54= Number obtained by reversing the digits
⇒10y+x−54=10x+y
⇒9x−9y=−54
⇒x−y=−6 ---(2)
Putting y=3x in equation (2), we get x−3x=−6⇒x=3
Putting x = 3 in equation (1), we get y = 9 hence number = 10y + x = 10 x 9 + 3 = 93
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