Question

Find a two-digit number, if its units digit exceeds the tens digit by two and the difference of the desired number and the sum of its digits is equal to 18.

Please Do not use y As Tens or ones please use Tens =x And Ones =x+2​

Answer 1

$\large \underline{ \underline{ \text{Question:}}}$

• Find a two-digit number, if its units digit exceeds the tens digit by two and the difference of the desired number and the sum of its digits is equal to 18.

$\large \underline{ \underline{ \text{Solution:}}}$

Let's,

• The Tens digit of the number be 'x'.

Then,

• The Unit digit of the number should be 'x + 2'.

Finding the number,

$\implies \text{The Number} = 10( \text{Tens digit}) + 1( \text{Unit digit}) \\ \\ \implies \text{The Number} = 10x + x + 2 \\ \\ \implies \boxed{\text{The Number} = 11x + 2}$

Finding the sum of digits,

$\implies \text{The Sum} = \text{Tens digit} + \text{Unit digit} \\ \\ \implies \text{The Sum} = x + x + 2 \\ \\ \implies \boxed{\text{The Sum} = 2x + 2}$

According to Question,

$\implies \text{Number} - \text{Sum of digits} = 18 \\ \\ \implies (11x + 2) - (2x + 2) = 18 \\ \\ \implies 11x - 2x + 2 - 2 = 18 \\ \\ \implies 9x = 18 \\ \\\implies x = \frac{18}{9} \\ \\ \implies \boxed{x = 2}$

Hence,

• The value of 'x' is 2.

Finding the Number,

• ➤ The Number = 11x + 2

• ➤ The Number = 11(2) + 2

• ➤ The Number = 22 + 2

• ➤ The Number = 24

Therefore,

• The Number is equals to 24.

$\\ \large \underline{ \underline{ \text{Required Answer:}}}$

• The Number is equals to 24.