Find a two-digit number, if its units digit exceeds the tens digit by two and the difference of the desired number and the sum of its digits is equal to 18. PLEASE TENS AS x And ONES AS x+2
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Let the units digit be x+2 and tens digit be x
Therefore, the number is 10x+x+2=11x+2
Sum of the digits is x+2+x=2x+2
According to the problem, (11x+2)-(2x+2)=18
=>9x=18
=>x=2
The number is 11*2+2=24.
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Therefore, the number is 10x+x+2=11x+2
Sum of the digits is x+2+x=2x+2
According to the problem, (11x+2)-(2x+2)=18
=>9x=18
=>x=2
The number is 11*2+2=24.
PLEASE MARK ME BRAINLIEST
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