Find a two-digit numbers divisibly by 3
if the tens digit is 8
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Step-by-step explanation:
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Hi dear
Let the unit digit be x
Tens digit = 8
So, the no. is 8x
Divisibility by 3 -
If the sum of digits is a multiple of 3 then the whole no. will be divisible by 3.
The no. is 8x
Sum of digits = 8+x
By keeping the value of x as 1,4,7 The no. gets divisible by 3.
So the no. are 81,84 and 87
Hope it helps you.
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