Find a unit vector in the direction of A=3i+6j-2k
Answers
Answered by
6
 (Unit vector) = Vector A/ Magnitude of Vec. A
= 3i + 6j - 2k/√(3^2 + 6^2 + 2^2)
= 3i + 6j - 2k/49 ..... Ans.
Thank me later !
Practice it quick exams are near .
= 3i + 6j - 2k/√(3^2 + 6^2 + 2^2)
= 3i + 6j - 2k/49 ..... Ans.
Thank me later !
Practice it quick exams are near .
Similar questions