find a unit vector parallel to vector A= 2i-3j+6k
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just calculate the unit vector of the given vector......since the unit vector is of the given vector..so it must be parallel.
hope this will help you
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Answer:-0.29i+0.43j-0.86k
Explanation:
unit vector = A/|A|
=2i-3j+6k/√2²+(-3)²+6²
=2i-3j+6k/7
=0.29i-0.43j+0.86k
Unit vector parallel to vector 2i-3j+6k is -0.29i+0.43j-0.86k
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