Find a unit vector perpendicular to the vectors j+2k and î +1.
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axb
I J K
0 1 2
1 1 0
= -2i +2j -k
|axb| = square root 4+4+1 =3
Unit vector perpendicular to a&b is
-2/3i+2/3j -1/3 k
I J K
0 1 2
1 1 0
= -2i +2j -k
|axb| = square root 4+4+1 =3
Unit vector perpendicular to a&b is
-2/3i+2/3j -1/3 k
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