Math, asked by dhivakar8012359010, 1 month ago

find 'a 'value of[(3x+2)^2D^2+3(3x+2)D-36]y=3x^2+4x+1

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Answered by Anonymous

Answer:

Legendre’s equation ((3x + 2)2D2 + 3(3x + 2)D – 36)y = (3x2 + 4x + 1) … (1) Read more on Sarthaks.com - https://www.sarthaks.com/388569/solve-3x-2-2d-2-3-3x-2-d-36-y-3x-2-4x-1

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find 'a 'value of[(3x+2)^2D^2+3(3x+2)D-36]y=3x^2+4x+1​

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find 'a 'value of[(3x+2)^2D^2+3(3x+2)D-36]y=3x^2+4x+1