Math, asked by ramalingam61, 3 months ago

find a value of log (1+i)​

Answers

Answered by sakibulmandal
2

Step-by-step explanation:

log (1 + i) = ln √ 2+(π/4+2kπ)i = (1/2) ln 2 + (8k + 1)πi/4. Thus, to the complex number 1+i, the logarithm function assigns an infinite number of values, log (1 + i) = (1/2) ln 2 + (8k + 1)πi/4.

Similar questions