find a value of log (1+i)
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Step-by-step explanation:
log (1 + i) = ln √ 2+(π/4+2kπ)i = (1/2) ln 2 + (8k + 1)πi/4. Thus, to the complex number 1+i, the logarithm function assigns an infinite number of values, log (1 + i) = (1/2) ln 2 + (8k + 1)πi/4.
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