Question

Find a vector of magnitude 26 units normal to the plane 12x-3y+4z= 1.

Answer 1

Unit vector perpendicular to the plane 12 x - 3y + 4z = 1 is
           u   =    (12 i - 3 j + 4 k ) / √(12²+3²+4² )

Vector of magnitude 26 will be = 26 u
 
     So ,    24 i - 6 j + 8 k   is the answer