Find a vector which is parallel and perpendicular to both -i-j and 2i - 5j
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Answer:
Here is your answer.
Step-by-step explanation:
We know that a × b is a vector perpendicular to the plane of a and b
Therefore, unit vector perpendicular to the plane of a and b is a×b/|a×b|
Now a × b = (- i - j) × (2i – 5j)
= 5i - 2j
Unit vector parallel to a × b
= (a×b)/(|a×b|)
= 5i - 2j/√21
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