Physics, asked by aneesahmed3327, 9 months ago

Find a vector which is parallel to A vector= 4i-3j and has same magnitude as B vector 8i+6j

Answers

Answered by nithin280503
1

Answer:

8i-6j

Explanation:

Let the required vector be X.

If X is parallel to A then

    A = k.X                        (k is some Constant)

Magnitude of X = Magnitude of B

     Magnitude of B = \sqrt{8^{2} + 6^{2} }= 10

Magnitude of X = 10

Now consider ,      A = k.X

Taking magnitude on both sides we get,

Magnitude of A= k(Magnitude of X)

     5 = k (10) ⇒ k=1/2

So    A = 1/2(X) ⇒ X = 2A

X = 2(4i-3j) = 8i-6j

Answered by aneetavaidyan7
0

Answer

8i-6j

Explanation:

Let the required vector be X.

If X is parallel to A then

A = k.X (k is some Constant)

Magnitude of X = Magnitude of B

Magnitude of B = = 10

Magnitude of X = 10

Now consider , A = k.X

Taking magnitude on both sides we get,

Magnitude of A= k(Magnitude of X)

5 = k (10) ⇒ k=1/2

So A = 1/2(X) ⇒ X = 2A

X = 2(4i-3j) = 8i-6j

Similar questions