Question

Find a vector which is parallel to v=i-2j
and has a magnitude 10.​

Answer 1

REFER THE ATTACHMENT

THANKS !!!!!!!!

Answer 2

Answer:

$\frac{10\hat{i}}{\sqrt5}-\frac{20\hat{j}}{\sqrt5}$

Explanation:

We are given that a  vector

$\vec{v}=\hat{i}-2\hat{j}$

We have to find a vector which is parallel to given vector and has magnitude 10.

$\mid \vec{v}\mid=\sqrt(1)^2+(-2)^2=\sqrt5$

$\hat{v}=\frac{\vec{v}}{\mid \vec{v}\mid}$

$\hat{v}=\frac{\hat{i}-2\hat{j}}{\sqrt5}$

We are given that a vector has magnitude= 10

$10\cdot\hat{v}=\frac{10\hat{i}}{\sqrt5}-\frac{20\hat{j}}{\sqrt5}$

Hence, the vector parallel to given vector with magnitude 10 is given by

$\frac{10\hat{i}}{\sqrt5}-\frac{20\hat{j}}{\sqrt5}$