Find a word worth ₹ 0.60 when A=0.01, B=0.02, C=0.03 ,...
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Step-by-step explanation:
t1=o.o1, tn=o.60
t2=0.02
D=t2-t1=0.02-0.01
=0.01
we known that ,
tn=a+(n-1)d
0.60=0.01+(n-1)0.01
0.60=0.01+0.01n - 0.01 * 0.01
0.60-0.01=0.01n *0.01
0.59=0.01n
0.59\0.01=n
0.59=n
hence the letter will be D
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