Question

Find a zero of polynomial x^2+4
(By factorising)
I will surely mark as brainliest if you give the correct answer

Answer 1

Answer:

-2

Step-by-step explanation:

x^2+4=0

x^2=-4

x=√-4

x=-2

Verify:

(-2)^2+4= 4-4=0

Hopefully it helps you!!

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Answer 2

$Given \: Quadratic \: polynomial : p(x) = x^{2} + 4$

$For \: any \: real \: value \: of \: x \: p(x) \: is \\not \: equal \: to \: zero$

$Compare \: p(x) \: with \:ax^{2}+bx+c , we \:get$

$a = 1 , \:b = 0\: and \: c = 4$

$Discreminant (D) = b^{2} - 4ac \\= 0 - 4\times 1 \times 4 \\= - 16$

D < 0 ,

Therefore.,

$No \: real \: zeroes$

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