Question

find a2,a3,a4,a5 if a1=-4 and a6 =6

Answer 1

Answer:

5.6

Step-by-step explanation:

a1=-4

a6=6

a+5d=6

4+5d=6

5d=6-4

5d=2

d=2/5=0.4

a2=a+d=4+0.4=4.4

a3=a+2d=4+2(0.4)=4.8

a4=a+3d=4+3(0.4)=5.2

a5=a+4d=4+4(0.4)=5.6

Answer 2

Answer:

Here a₂= 4+(2/5) = 4.4

a₃= 4.8

a₄= 5.2

a₅= 5.6

Step-by-step explanation:

We know, aₙ=a+(n-1)d

Here a₁ = a=4

a₂= a+(2-1)d= a+d=4+d......(i)

a₃=a+(3-1)d=a+2d=4+2d......(ii)

a₄=a+(4-1)d= a+3d.....(iii)

a₅=a+(5-1)d= a+4d....(iv)

a₆=a+(6-1)d= a+5d=6 ( given)

Now a=4

So, 4+5d=6

d= 2/5

Puting value of a and d in equation (i),(ii),(iii) and (iv) and get

a₂= 4+(2/5) = 4.4

a₃=a+(3-1)d=a+2d= 4+2×(2/5)= 4.8

a₄=a+(4-1)d= a+3d= 4+3×(2/5)= 5.2

a₅=a+(5-1)d= a+4d= 4+4×(2/5)= 5.6