find (a³+27) if a+9/a=3
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a^3+b^3=(a+b) (a^2-ab+b^2)
(a^3+3^3)=(a+3) (a^2-3a+9)
Given a+9/a=3
Ie. a^2+9-3a=0
So
a^3+3^3= (a+3) (0)
=0
(a^3+3^3)=(a+3) (a^2-3a+9)
Given a+9/a=3
Ie. a^2+9-3a=0
So
a^3+3^3= (a+3) (0)
=0
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