Question

Find (a³+b³)/b³

please give this Answer I beg you


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Answer 1

Answer:

(a³+b³)/b³=[(a/b)+1][(a²/b²)-(a/b)+1]

Step-by-step explanation:

Given that :-

(a³+b³)/b³

=>(a³/b³)+(b³/b³)

=>(a³/b³)+1

or

=>(a/b)³+1

It can be written as

=>(a/b)³+1³

This is in the form of x³+y³

we know that

x³+y³=(x+y)(x²-xy+y²)

(a/b)³+1³=[(a/b)+1][(a/b)²-(a/b)(1)+1²]

=>[(a/b)+1][(a²/b²)-(a/b)+1]

(a³+b³)/b³=[(a/b)+1][(a²/b²)-(a/b)+1]