Find a6 term from the geometric sequence a1=4 a3=36
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....Thank you............
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a=d
a3=a+2d
we subtracting the equation 2 and 1
a +2d - a =36-4
2d= 32
d=16
then find
a6 =a+5d
a6= 4 + 5 *16
= 84
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