find ab if a=1,2,3,1,-2,-3and b=1,-1,1,2,1,-2examine whether has inverse or not
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Answer:
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Answered by
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Answer:
AB=(
1
1
2
−2
3
−3
)×B=
⎝
⎜
⎜
⎛
1
1
1
−1
2
−2
⎠
⎟
⎟
⎞
=[
1(1)+2(1)+3(1)
1(1)+(−2)(1)+(−3)(1)
1(−1)+2(2)+3(−2)
(1)(−1)+(−2)(2)+(−3)(−2)
]
=[
1+2+3
1−2−3
−1+4−6
−1−4+6
]
=[
6
−4
−3
1
]
∴∣AB∣=
∣
∣
∣
∣
∣
∣
6
−4
−3
1
∣
∣
∣
∣
∣
∣
=6−12=−6
=0
∴AB is a non-singular matrix.
Hence, (AB)
−1
exists.
Step-by-step explanation:
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