Question

Find AB in the adjoining figure

Answer 1

Answer:

$20 \sqrt{3}$

Step-by-step explanation:

in given figure :

CD = AD = 40

in triangle ABD:

Sin 60° = P/H = AB / AD

$\frac{ \sqrt{3} }{2} = \frac{ab}{40}$

$2ab = \sqrt{3} \times 40$

$ab = 20 \sqrt{3}$