Question

Find AB in the given figure​

Answer 1

Step-by-step explanation:

FC/AC = tan45 = 1

then, AC = FC = 20,

ED/DB = tan60 = √3 = 1.73

DB = ED/1.73 = 30/1.73 = 17.34

If it is assumed that a straight line from F which is parallel to CD will then intersect at ED on a point P. A triangle PEF will form.

in ∆PEF, PF/PE = tan60 = 1.73

PF = PE*1.73 = (ED - FC)*1.73 = 10*1.73 = 17.3

Then PF = CD = 17.3

AB = AC + CD + DB

= 20 + 17.3 + 17.34

= 54.64