Question

find AB in the triangle abc angle b is 90° and BD is perpendicular to AC ,AD=4 cm and BC is 9 cm​

Answer 1

Step-by-step explanation:

Given:

∠ABC=90o,BD⊥AC,

BD=8 and AD=4 as in diagram.

Let ∠ACB=x

⇒∠CBD=90−x

⇒∠ABD=x

⇒∠BAD=90−x

⇒ΔABC,ΔADB and ΔBDC are similar

⇒CDBD=DBAD

⇒CD8=84

⇒CD=48×8=16cm.