Question

Find abc such that following numbers are in ap
a,7,b,23,c​

Answer 1

Answer:

a+b+c=−1+15+31=45

Step-by-step explanation:

Since a,7,b,23,c are in AP.

∴7−a=b−7=23−b=c−23 ....(1)

On taking 2

nd

and 3

rd

expression, we get,

b−7=23−b

⇒2b=30⇒b=15

On taking 1

st

and 2

nd

expression, we get,

7−a=b−7

⇒7−a=15−7⇒a=−1

Again, on taking 3

rd

and 4

th

expression, we get,

23−b=c−23

⇒23−15=c−23⇒c=31

Hence a=−1,b=15,c=31

∴a+b+c=−1+15+31=45