Find ABCD given that BC = 5 cm, CD = 4 cm, ∠A = 75°, ∠B = 120° and ∠D = 85º. Measure AB and DA
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⇒ Draw a line segment AB = 6cm.
⇒ With B as a center and radius BC = 4cm, draw an arc.
⇒ With A as a center and radius AC = 8cm, draw an arc intersecting the previous arc at point C.
⇒ Again take B as a center and radius BD = 7cm, draw an arc.
⇒ With C as a center and radius CD = 7cm, draw an arc intersecting the previous arc at point D.
⇒ Join AC, BC, BD, CD and AD.
Thus, ABCD is a required quadrilateral
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