Question

Find abscissa of point whose ordinate is 4 and which are at distance of 5 units from 5,0

Answer 1

Hi use the distance formula.
Let (x,4) be the point.
Given it is 5 units far from point (5,0)
Therefore
$\sqrt{ {(x - 5)}^{2} + {(4 - 0)}^{2} } = 5 \\ {(x - 5)}^{2} + {4}^{2} = 25 \\ {(x - 5)}^{2} = 9 \\ x - 5 = 3 \: or \: - 3 \\ x = 8 \: or \: - 2$
Hope this helps.

Answer 2

Answer will be 2 or 8 as shown in the solution.. Thanku!!