find acceleration and distance covered an object starts with 36 kmph and attains 72 kmph in 10sec
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Answered by
2
Answer:
a = v-u/t
a= 72- 36/10
a = 36/10
a = 3.6 m/s^2
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Answered by
1
72 kmph = 20mph
36kmph=10mph
a=v-u/ t
ie 20-10/10
acceleration is 1 m/s²
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