Question

find acceleration and velocity at 2sec of the motion of an object having displacement function x(t)=(5t²+3t-2)​

Answer 1

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■ SOLUTION:-

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The displacement is given as

$x=5t ^{2} +4t+3$

$⇒x−3=5t ^{2} +4t$

assuming x−3=s,

$s=4t+ \frac{1}{2} 10t ^{2}$

comparing this with

$s=ut+ \frac{1}{2} at ^{2}$

we get 

$u=4m/s and a=10m/s ^{2}$

so velocity at t=2sec is 

v=u+at=4+10×2=24m/s

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