find acceleration due to gravity at a height of 12, 800km from the surface of earth.Earth's radius=6400km
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F = m g' = G M_e m / (R+d)²
m = mass of an object at a distance d from the surface of Earth.
M_e = mass of Earth.
G = universal gravitational constant.
R = radius of Earth
g' = G M_e / (R + d)²
let g = acceleration due to gravity at the surface of Earth
m g = G M m /R²
=> g = G M_e / R²
g' / g = R² / (R+d)² = 6400² / (6400+12800)² = 1/9
g' = g / 9 = 9.81/9 = 1.09 m/s² taking g = 9.81 m/s²
m = mass of an object at a distance d from the surface of Earth.
M_e = mass of Earth.
G = universal gravitational constant.
R = radius of Earth
g' = G M_e / (R + d)²
let g = acceleration due to gravity at the surface of Earth
m g = G M m /R²
=> g = G M_e / R²
g' / g = R² / (R+d)² = 6400² / (6400+12800)² = 1/9
g' = g / 9 = 9.81/9 = 1.09 m/s² taking g = 9.81 m/s²
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